5f67d9ba47ad2922ee409087

solve for x

@parmu

if it's given that y = x^2 + 3 = 0 What is the value of x?

What's given is x^2 + 3 = 0 . With some rearranging we get this: x^2 = -3 This is a quadratic equation so it has 2 solutions => x = +sqrt(-3) or -sqrt(-3) => x = i x sqrt(3) or -i sqrt(3) Both solutions hare outside Real numbers set.

@parmu2